9x^2+x=10

Solution for 9x^2+x=10 equation:

9x^2+x=10

We move all terms to the left:

9x^2+x-(10)=0

a = 9; b = 1; c = -10;
Δ = b2-4ac
Δ = 12-4·9·(-10)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-19}{2*9}=\frac{-20}{18}
=-1+1/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+19}{2*9}=\frac{18}{18}
=1
$